ucsgears

UCS_Fridays

A simple script to show the Fridays (Weekly Option Expiry), of course this is a basic script we can make a few more improvement.

One of many ways to utilize the "dayofweek" variable.

Currently there are no options to draw a vertical line, you can do a background color for the candle.

Future plans - Include monthly option expiry.
開源腳本

秉持真正的TradingView精神,該腳本的作者將其開源發佈,因此交易者可以理解和驗證它。為作者加油!您可以免費使用它,但是在發佈中重複使用此程式碼受網站規則的約束。您可以把它加入到常用以在圖表上使用它。

想在圖表上使用此腳本?
// Created by UCSgears
// Simple script to show you Fridays (Weekly Options Expiry)
// Will release a version for Monthly Option Expiry

study("UCS_Fridays", overlay = true)

x = dayofweek == 6 ? 1 : 0

plotshape(x, style = shape.xcross, location = location.top, title="Show Me Fridays")

評論

cool...and I remember there is a script in the library that colors each day too, so perhaps a different color for each Friday through the month. I use the same notification for FX and Fix rates.
+2 回覆
Nice work -- I have to admit I got super excited when I saw the title because I was trying to program a OPEX marker, but was only able to determine every Friday, not every third Friday because despite all the choices there is no ' ' weekokmonth ' variable. Admittedly I didn't spend an inordinate amount of time on it, but now that you;ve jogged my memory maybe I'll try again this afternoon.

Good stuff.
+1 回覆
ucsgears SPYderCrusher
I am starting to work on it as well. Primarily for options.
+1 回覆
Sweet. I outlined a thought process for how one could do it below, curious to see what you come up with or if that was basically your plan as well. Cheers.
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any ideas for plotting expirations for future dates? not just current bar and previous.
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I guess you could do weekofyear, and do like a if <4 then 3, if > 4, then n placeholder +3 something along those lines
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SPYderCrusher SPYderCrusher
greater than and less than symbols didnt show but it should be if less than 4 then n is 3 and if greater than 4 then n placeholder plus 3 (on the assuming 3 would be the third week of the year + friday, then can just add four to that to get February's third friday etc).
+1 回覆
ucsgears SPYderCrusher
I was thinking more basic, dayofmonth and friday. It should work theoretically.
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